Logic
- The statement P→Q doesn’t necessarily mean that Q→P. Suppose that a is some integer and consider the statements:
- (a is a multiple of 6) → (a is divisible by 2),
- (a is divisible by 2) → (a is a multiple of 6).
- The first statement is true while the second one is false.
- Sometimes the converse is true.
- (a is even) → (a is divisible by 2),
- (a is divisible by 2) → (a is even)
- Since both P→Q andQ→P are true, it follows that (P→Q) ∧ (Q→P) is true.
- The symbol for a biconditional statement is ⟺ which is read as if and only if
Truth Table