Direct Proof
Introduction
Example 1
- Proposition: If x is odd, then x2 is odd.
- Proof. Suppose x is odd
- Then x=2a+1 for some a∈Z, by definition of an odd number
- Thus x2=(2a+1)2=4a2+4a+1=2(2a2+2a)+1.
- So x2=2b+1 where b is the integer b=2a2+2a
- Thus x2=2b+1 for an integer b.
Example 2
- Proposition: Let a, b and c be integers. If a∣b and b∣c, then a∣c.
- Proof. Suppose a∣b and b∣c.
- By Definition 4.4, we know a∣b means b=ad for some d∈Z.
- Likewise, b∣c means c=be for some e∈Z.
- Thus c=be=(ad)e=a(de), so c=ax for the integer x=de.
- Therefore a∣c.