Proofs Involving Sets Example Let’s investigate elements of A={x:x∈N∧7∣x}. This set has form A=x:P(x) where P(x) is the open sentence (x∈N)∧(7∣x). Thus 21∈A because P(21) is true. Similarly, 7,14,28,35, etc., are all elements of A. But 8∈/A (for example) because P(8) is false. Likewise −14∈/A because P(−14) is false.